Integrand size = 25, antiderivative size = 81 \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {\arctan \left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{a \sqrt {d} f}+\frac {\text {arctanh}\left (\frac {\sqrt {d} (1+\tan (e+f x))}{\sqrt {2} \sqrt {d \tan (e+f x)}}\right )}{\sqrt {2} a \sqrt {d} f} \]
[Out]
Time = 0.22 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {3655, 3613, 214, 3715, 65, 211} \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {\arctan \left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{a \sqrt {d} f}+\frac {\text {arctanh}\left (\frac {\sqrt {d} (\tan (e+f x)+1)}{\sqrt {2} \sqrt {d \tan (e+f x)}}\right )}{\sqrt {2} a \sqrt {d} f} \]
[In]
[Out]
Rule 65
Rule 211
Rule 214
Rule 3613
Rule 3655
Rule 3715
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int \frac {1+\tan ^2(e+f x)}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx+\frac {\int \frac {a-a \tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx}{2 a^2} \\ & = \frac {\text {Subst}\left (\int \frac {1}{\sqrt {d x} (a+a x)} \, dx,x,\tan (e+f x)\right )}{2 f}-\frac {\text {Subst}\left (\int \frac {1}{-2 a^2+d x^2} \, dx,x,\frac {a+a \tan (e+f x)}{\sqrt {d \tan (e+f x)}}\right )}{f} \\ & = \frac {\text {arctanh}\left (\frac {\sqrt {d} (1+\tan (e+f x))}{\sqrt {2} \sqrt {d \tan (e+f x)}}\right )}{\sqrt {2} a \sqrt {d} f}+\frac {\text {Subst}\left (\int \frac {1}{a+\frac {a x^2}{d}} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{d f} \\ & = \frac {\arctan \left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{a \sqrt {d} f}+\frac {\text {arctanh}\left (\frac {\sqrt {d} (1+\tan (e+f x))}{\sqrt {2} \sqrt {d \tan (e+f x)}}\right )}{\sqrt {2} a \sqrt {d} f} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(283\) vs. \(2(81)=162\).
Time = 0.49 (sec) , antiderivative size = 283, normalized size of antiderivative = 3.49 \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {8 d^{3/2} \arctan \left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )+4 \left (-d^2\right )^{3/4} \arctan \left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt [4]{-d^2}}\right )-2 \sqrt {2} d^{3/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )+2 \sqrt {2} d^{3/2} \arctan \left (1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )-4 \left (-d^2\right )^{3/4} \text {arctanh}\left (\frac {\sqrt {d \tan (e+f x)}}{\sqrt [4]{-d^2}}\right )-\sqrt {2} d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )+\sqrt {2} d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{8 a d^2 f} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(303\) vs. \(2(67)=134\).
Time = 0.76 (sec) , antiderivative size = 304, normalized size of antiderivative = 3.75
method | result | size |
derivativedivides | \(\frac {2 d^{2} \left (\frac {\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 d}-\frac {\sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (d^{2}\right )^{\frac {1}{4}}}}{2 d^{2}}+\frac {\arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {d}}\right )}{2 d^{\frac {5}{2}}}\right )}{f a}\) | \(304\) |
default | \(\frac {2 d^{2} \left (\frac {\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 d}-\frac {\sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (d^{2}\right )^{\frac {1}{4}}}}{2 d^{2}}+\frac {\arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {d}}\right )}{2 d^{\frac {5}{2}}}\right )}{f a}\) | \(304\) |
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 209, normalized size of antiderivative = 2.58 \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\left [-\frac {\sqrt {2} \sqrt {-d} \arctan \left (\frac {\sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {-d} {\left (\tan \left (f x + e\right ) + 1\right )}}{2 \, d \tan \left (f x + e\right )}\right ) + \sqrt {-d} \log \left (\frac {d \tan \left (f x + e\right ) - 2 \, \sqrt {d \tan \left (f x + e\right )} \sqrt {-d} - d}{\tan \left (f x + e\right ) + 1}\right )}{2 \, a d f}, \frac {\sqrt {2} \sqrt {d} \log \left (\frac {d \tan \left (f x + e\right )^{2} + 2 \, \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} {\left (\tan \left (f x + e\right ) + 1\right )} + 4 \, d \tan \left (f x + e\right ) + d}{\tan \left (f x + e\right )^{2} + 1}\right ) + 4 \, \sqrt {d} \arctan \left (\frac {\sqrt {d \tan \left (f x + e\right )}}{\sqrt {d}}\right )}{4 \, a d f}\right ] \]
[In]
[Out]
\[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {\int \frac {1}{\sqrt {d \tan {\left (e + f x \right )}} \tan {\left (e + f x \right )} + \sqrt {d \tan {\left (e + f x \right )}}}\, dx}{a} \]
[In]
[Out]
none
Time = 0.31 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.36 \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {\frac {d {\left (\frac {\sqrt {2} \log \left (d \tan \left (f x + e\right ) + \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}} - \frac {\sqrt {2} \log \left (d \tan \left (f x + e\right ) - \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}}\right )}}{a} + \frac {4 \, \sqrt {d} \arctan \left (\frac {\sqrt {d \tan \left (f x + e\right )}}{\sqrt {d}}\right )}{a}}{4 \, d f} \]
[In]
[Out]
\[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\int { \frac {1}{{\left (a \tan \left (f x + e\right ) + a\right )} \sqrt {d \tan \left (f x + e\right )}} \,d x } \]
[In]
[Out]
Time = 5.06 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.96 \[ \int \frac {1}{\sqrt {d \tan (e+f x)} (a+a \tan (e+f x))} \, dx=\frac {\mathrm {atan}\left (\frac {\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{\sqrt {d}}\right )}{a\,\sqrt {d}\,f}+\frac {\sqrt {2}\,\mathrm {atanh}\left (\frac {12\,\sqrt {2}\,d^{9/2}\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{12\,d^5\,\mathrm {tan}\left (e+f\,x\right )+12\,d^5}\right )}{2\,a\,\sqrt {d}\,f} \]
[In]
[Out]